Well from a purely theoretical point - this is going to get me shot down in flames
Suppose your sink rate is 1.2 m/s - that's what my wing is.
Then the vertical component of wind required to keep you up as you soar parallel to the slope will need to be at least the same.
Suppose you don't fancy launching in more than 20mph (32 km/h which is about 9 m/s) - that's the wind speed up the slope - then the angle of the slope needs to be Sin(1.2/9) which is about 8 degrees. So the slope will be 1 in 1/(Tan 8deg) This is roughly 1 in 7.
Obviously the wind speed must be less than Vtrim of the wing (mine's 36 km/h) otherwise you are going backwards or gale hanging on speed bar (which will increase your sink rate........)
I tried soaring a local hill (Killhope Law) last year. This is about 1 in 8 and I only just managed to stay clear of the slope in nill wind, which proves that theory doesn't usually give practical answers as I should be able to do 1 in 10 on my wing - so all the above is rubbish really

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